Comments on: Easy JSON Encoding/Decoding in PHP

By: Doug

Doug — Mon, 22 Mar 2010 20:33:15 +0000

No one has mentioned that these are not core PHP functions. In order to get the JSON functions to work in PHP, you will have to install the JSON PECL PHP extension.

By: Cuong

Cuong — Sat, 19 Sep 2009 19:25:05 +0000

The main advantage of JSON format to me, as a web developer, is the simplicity of exchanging data in Ajax based interaction. What I normally do is at the server side bundle all the data in a PHP array, encode the array in JSON format, and output it. At client side, decode the output by the PHP script into an JavaScript object.

For more information see http://www.json.org/js.html.

After the release PHP 5.2, I only use PHP build-in function
json_encode for mostly all my JSON encoding needs. As far as I can recall, I have never used json_decode in PHP.

By: Web Design Bermuda

Web Design Bermuda — Thu, 17 Sep 2009 13:56:23 +0000

I do not understand how this demonstrates an advantage. It is easy to JSON encode simple strings like above.

Does Zend help with JSON encoding HTML or strings that need lots of escape characters.

I am having a really tough time right now JSON encoding a string of HTML with a checkbox array. The checkbox array contains square brackets which throw off the JSON.

How would Zend help me deal with this?

By: Tracy

Tracy — Wed, 17 Jun 2009 04:25:37 +0000

I'm trying to decode a JSON string into a PHP array. The JSON string is stored in a PHP variable. How do I format this line: $result = Zend_Json::decode( 'wine');
to use the variable containing the JSON string?

Thanks!

By: Martin

Martin — Wed, 10 Dec 2008 17:01:29 +0000

Hi thanks for your help. I got the same error, updatet php and now it is working.

Thx.

By: darksama

darksama — Fri, 11 Apr 2008 06:22:13 +0000

It sounds good, I love the simplicity. Your posts are easy as a pie and really attractive at the same time.

By: YUI Based Lightbox - Revisited : Code Central

YUI Based Lightbox - Revisited : Code Central — Thu, 13 Mar 2008 07:23:40 +0000

[...] Easy JSON Encoding/Decoding in PHP [...]

By: Cuong

Cuong — Mon, 21 Jan 2008 23:51:31 +0000

Both perform essentially the same thing. The only catch is that json_decode is not available in PHP prior to version 5.20.

By: Mike

Mike — Mon, 21 Jan 2008 23:37:48 +0000

So what does the Zend class do that the native PHP json_encode and json_decode functions don't? (Apart from being available in an earlier version of PHP)

By: Cuong

Cuong — Mon, 24 Dec 2007 20:18:15 +0000

Sorry your earlier comment was placed to moderation. I see what you are trying to do now.

Apparently this is a JSONP request. You have to wrap your entire JSON response with the callback you specified in the URL, which is "callback" in this case:

callback( {"job_Description":"My Job","job_Notes":"My jobs notes are here."} )

http://bob.pythonmac.org/archives/2005/12/05/remote-json-jsonp/

If cross-site scripting is not required, you can simply change this line from

var url = "http://127.0.0.1/projects/client_api/test?callback=?";

var url = "http://127.0.0.1/projects/client_api/test";